3x+2/3x=49

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Solution for 3x+2/3x=49 equation:



3x+2/3x=49
We move all terms to the left:
3x+2/3x-(49)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We multiply all the terms by the denominator
3x*3x-49*3x+2=0
Wy multiply elements
9x^2-147x+2=0
a = 9; b = -147; c = +2;
Δ = b2-4ac
Δ = -1472-4·9·2
Δ = 21537
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{21537}=\sqrt{9*2393}=\sqrt{9}*\sqrt{2393}=3\sqrt{2393}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-147)-3\sqrt{2393}}{2*9}=\frac{147-3\sqrt{2393}}{18} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-147)+3\sqrt{2393}}{2*9}=\frac{147+3\sqrt{2393}}{18} $

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