3x+2/4x=18

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Solution for 3x+2/4x=18 equation:



3x+2/4x=18
We move all terms to the left:
3x+2/4x-(18)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
We multiply all the terms by the denominator
3x*4x-18*4x+2=0
Wy multiply elements
12x^2-72x+2=0
a = 12; b = -72; c = +2;
Δ = b2-4ac
Δ = -722-4·12·2
Δ = 5088
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{5088}=\sqrt{16*318}=\sqrt{16}*\sqrt{318}=4\sqrt{318}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-4\sqrt{318}}{2*12}=\frac{72-4\sqrt{318}}{24} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+4\sqrt{318}}{2*12}=\frac{72+4\sqrt{318}}{24} $

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