3x+2/5=4-(x+2)/3

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Solution for 3x+2/5=4-(x+2)/3 equation:



3x+2/5=4-(x+2)/3
We move all terms to the left:
3x+2/5-(4-(x+2)/3)=0
We calculate fractions
3x+(-(4-(x+2)*5)/()+()/()=0
We calculate terms in parentheses: +(-(4-(x+2)*5)/()+()/(), so:
-(4-(x+2)*5)/()+()/(
We add all the numbers together, and all the variables
-(4-(x+2)*5)/()+1
We multiply all the terms by the denominator
-(4-(x+2)*5)+1*()
We calculate terms in parentheses: -(4-(x+2)*5), so:
4-(x+2)*5
determiningTheFunctionDomain -(x+2)*5+4
We multiply parentheses
-5x-10+4
We add all the numbers together, and all the variables
-5x-6
Back to the equation:
-(-5x-6)
We add all the numbers together, and all the variables
-(-5x-6)
We get rid of parentheses
5x+6
Back to the equation:
+(5x+6)
We get rid of parentheses
3x+5x+6=0
We add all the numbers together, and all the variables
8x+6=0
We move all terms containing x to the left, all other terms to the right
8x=-6
x=-6/8
x=-3/4

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