3x+2/x-1+3=4

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Solution for 3x+2/x-1+3=4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x+2/x-1+3 = 4 // - 4

3*x+2/x-4-1+3 = 0

3*x^1+2*x^-1-2*x^0 = 0

(3*x^2-2*x^1+2*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2-2*x^1+2*x^0) = 0

x^1

3*x^2-2*x+2 = 0

3*x^2-2*x+2 = 0

DELTA = (-2)^2-(2*3*4)

DELTA = -20

DELTA < 0

x in { } 

x belongs to the empty set

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