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3x+2/x-5=20
We move all terms to the left:
3x+2/x-5-(20)=0
Domain of the equation: x!=0We add all the numbers together, and all the variables
x∈R
3x+2/x-25=0
We multiply all the terms by the denominator
3x*x-25*x+2=0
We add all the numbers together, and all the variables
-25x+3x*x+2=0
Wy multiply elements
3x^2-25x+2=0
a = 3; b = -25; c = +2;
Δ = b2-4ac
Δ = -252-4·3·2
Δ = 601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{601}}{2*3}=\frac{25-\sqrt{601}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{601}}{2*3}=\frac{25+\sqrt{601}}{6} $
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