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3x+2/x=9
We move all terms to the left:
3x+2/x-(9)=0
Domain of the equation: x!=0We multiply all the terms by the denominator
x∈R
3x*x-9*x+2=0
We add all the numbers together, and all the variables
-9x+3x*x+2=0
Wy multiply elements
3x^2-9x+2=0
a = 3; b = -9; c = +2;
Δ = b2-4ac
Δ = -92-4·3·2
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{57}}{2*3}=\frac{9-\sqrt{57}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{57}}{2*3}=\frac{9+\sqrt{57}}{6} $
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