3x+20+2x=-3(x-5)+x

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Solution for 3x+20+2x=-3(x-5)+x equation: 



3x+20+2x=-3(x-5)+x

We move all terms to the left:

3x+20+2x-(-3(x-5)+x)=0

We add all the numbers together, and all the variables

5x-(-3(x-5)+x)+20=0



We calculate terms in parentheses: -(-3(x-5)+x), so:

-3(x-5)+x

We add all the numbers together, and all the variables

x-3(x-5)

We multiply parentheses

x-3x+15

We add all the numbers together, and all the variables

-2x+15

Back to the equation:

-(-2x+15)



We get rid of parentheses

5x+2x-15+20=0

We add all the numbers together, and all the variables

7x+5=0

We move all terms containing x to the left, all other terms to the right

7x=-5

x=-5/7

x=-5/7

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