3x+20=100-2x

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Solution for 3x+20=100-2x equation: 



3x+20=100-2x

We move all terms to the left:

3x+20-(100-2x)=0

We add all the numbers together, and all the variables

3x-(-2x+100)+20=0

We get rid of parentheses

3x+2x-100+20=0

We add all the numbers together, and all the variables

5x-80=0

We move all terms containing x to the left, all other terms to the right

5x=80

x=80/5

x=16

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