3x+20=1x-64

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Solution for 3x+20=1x-64 equation: 



3x+20=1x-64

We move all terms to the left:

3x+20-(1x-64)=0

We add all the numbers together, and all the variables

3x-(x-64)+20=0

We get rid of parentheses

3x-x+64+20=0

We add all the numbers together, and all the variables

2x+84=0

We move all terms containing x to the left, all other terms to the right

2x=-84

x=-84/2

x=-42

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