3x+20=60+(x-10)

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Solution for 3x+20=60+(x-10) equation:



3x+20=60+(x-10)
We move all terms to the left:
3x+20-(60+(x-10))=0
We calculate terms in parentheses: -(60+(x-10)), so:
60+(x-10)
determiningTheFunctionDomain (x-10)+60
We get rid of parentheses
x-10+60
We add all the numbers together, and all the variables
x+50
Back to the equation:
-(x+50)
We get rid of parentheses
3x-x-50+20=0
We add all the numbers together, and all the variables
2x-30=0
We move all terms containing x to the left, all other terms to the right
2x=30
x=30/2
x=15

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