3x+22=6(x+2)+4

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Solution for 3x+22=6(x+2)+4 equation: 



3x+22=6(x+2)+4

We move all terms to the left:

3x+22-(6(x+2)+4)=0



We calculate terms in parentheses: -(6(x+2)+4), so:

6(x+2)+4

We multiply parentheses

6x+12+4

We add all the numbers together, and all the variables

6x+16

Back to the equation:

-(6x+16)



We get rid of parentheses

3x-6x-16+22=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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