3x+22=6x-4(x-7)

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Solution for 3x+22=6x-4(x-7) equation: 



3x+22=6x-4(x-7)

We move all terms to the left:

3x+22-(6x-4(x-7))=0



We calculate terms in parentheses: -(6x-4(x-7)), so:

6x-4(x-7)

We multiply parentheses

6x-4x+28

We add all the numbers together, and all the variables

2x+28

Back to the equation:

-(2x+28)



We get rid of parentheses

3x-2x-28+22=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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