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3x+22=6x-4(x-7)
We move all terms to the left:
3x+22-(6x-4(x-7))=0
We calculate terms in parentheses: -(6x-4(x-7)), so:We get rid of parentheses
6x-4(x-7)
We multiply parentheses
6x-4x+28
We add all the numbers together, and all the variables
2x+28
Back to the equation:
-(2x+28)
3x-2x-28+22=0
We add all the numbers together, and all the variables
x-6=0
We move all terms containing x to the left, all other terms to the right
x=6
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