3x+23+9x-3=(7x-26)*2

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Solution for 3x+23+9x-3=(7x-26)*2 equation: 



3x+23+9x-3=(7x-26)*2

We move all terms to the left:

3x+23+9x-3-((7x-26)*2)=0

We add all the numbers together, and all the variables

12x-((7x-26)*2)+20=0



We calculate terms in parentheses: -((7x-26)*2), so:

(7x-26)*2

We multiply parentheses

14x-52

Back to the equation:

-(14x-52)



We get rid of parentheses

12x-14x+52+20=0

We add all the numbers together, and all the variables

-2x+72=0

We move all terms containing x to the left, all other terms to the right

-2x=-72

x=-72/-2

x=+36

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