3x+24=7.4/3x

Solution for 3x+24=7.4/3x equation:

3x+24=7.4/3x

We move all terms to the left:

3x+24-(7.4/3x)=0


Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3x-(+7.4/3x)+24=0

We get rid of parentheses

3x-7.4/3x+24=0

We multiply all the terms by the denominator


3x*3x+24*3x-7.4=0

Wy multiply elements

9x^2+72x-7.4=0

a = 9; b = 72; c = -7.4;
Δ = b2-4ac
Δ = 722-4·9·(-7.4)
Δ = 5450.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-\sqrt{5450.4}}{2*9}=\frac{-72-\sqrt{5450.4}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+\sqrt{5450.4}}{2*9}=\frac{-72+\sqrt{5450.4}}{18}
$