3x+25x2=80

Solution for 3x+25x2=80 equation:

3x+25x^2=80

We move all terms to the left:

3x+25x^2-(80)=0

a = 25; b = 3; c = -80;
Δ = b2-4ac
Δ = 32-4·25·(-80)
Δ = 8009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{8009}}{2*25}=\frac{-3-\sqrt{8009}}{50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{8009}}{2*25}=\frac{-3+\sqrt{8009}}{50}
$