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3x+2=(2x+13)/13
We move all terms to the left:
3x+2-((2x+13)/13)=0
We multiply all the terms by the denominator
3x*13)-((2x+13)+2*13)=0
We add all the numbers together, and all the variables
3x*13)-((2x+13)=0
Wy multiply elements
39x^2=0
a = 39; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·39·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{78}=0$
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