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3x+2=2(1-x)
We move all terms to the left:
3x+2-(2(1-x))=0
We add all the numbers together, and all the variables
3x-(2(-1x+1))+2=0
We calculate terms in parentheses: -(2(-1x+1)), so:We get rid of parentheses
2(-1x+1)
We multiply parentheses
-2x+2
Back to the equation:
-(-2x+2)
3x+2x-2+2=0
We add all the numbers together, and all the variables
5x=0
x=0/5
x=0
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