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3x+2=2(x+4)+4
We move all terms to the left:
3x+2-(2(x+4)+4)=0
We calculate terms in parentheses: -(2(x+4)+4), so:We get rid of parentheses
2(x+4)+4
We multiply parentheses
2x+8+4
We add all the numbers together, and all the variables
2x+12
Back to the equation:
-(2x+12)
3x-2x-12+2=0
We add all the numbers together, and all the variables
x-10=0
We move all terms containing x to the left, all other terms to the right
x=10
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