3x+2=2+(3-2x)

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Solution for 3x+2=2+(3-2x) equation: 



3x+2=2+(3-2x)

We move all terms to the left:

3x+2-(2+(3-2x))=0

We add all the numbers together, and all the variables

3x-(2+(-2x+3))+2=0



We calculate terms in parentheses: -(2+(-2x+3)), so:

2+(-2x+3)

determiningTheFunctionDomain
(-2x+3)+2

We get rid of parentheses

-2x+3+2

We add all the numbers together, and all the variables

-2x+5

Back to the equation:

-(-2x+5)



We get rid of parentheses

3x+2x-5+2=0

We add all the numbers together, and all the variables

5x-3=0

We move all terms containing x to the left, all other terms to the right

5x=3

x=3/5

x=3/5

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