3x+2=3(2x+1)+2

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Solution for 3x+2=3(2x+1)+2 equation: 



3x+2=3(2x+1)+2

We move all terms to the left:

3x+2-(3(2x+1)+2)=0



We calculate terms in parentheses: -(3(2x+1)+2), so:

3(2x+1)+2

We multiply parentheses

6x+3+2

We add all the numbers together, and all the variables

6x+5

Back to the equation:

-(6x+5)



We get rid of parentheses

3x-6x-5+2=0

We add all the numbers together, and all the variables

-3x-3=0

We move all terms containing x to the left, all other terms to the right

-3x=3

x=3/-3

x=-1

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