3x+2=42+2(x+5)

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Solution for 3x+2=42+2(x+5) equation: 



3x+2=42+2(x+5)

We move all terms to the left:

3x+2-(42+2(x+5))=0



We calculate terms in parentheses: -(42+2(x+5)), so:

42+2(x+5)

determiningTheFunctionDomain
2(x+5)+42

We multiply parentheses

2x+10+42

We add all the numbers together, and all the variables

2x+52

Back to the equation:

-(2x+52)



We get rid of parentheses

3x-2x-52+2=0

We add all the numbers together, and all the variables

x-50=0

We move all terms containing x to the left, all other terms to the right

x=50

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