3x+2=6(x-1)+8-3x

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Solution for 3x+2=6(x-1)+8-3x equation: 



3x+2=6(x-1)+8-3x

We move all terms to the left:

3x+2-(6(x-1)+8-3x)=0



We calculate terms in parentheses: -(6(x-1)+8-3x), so:

6(x-1)+8-3x

determiningTheFunctionDomain
6(x-1)-3x+8

We add all the numbers together, and all the variables

-3x+6(x-1)+8

We multiply parentheses

-3x+6x-6+8

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We get rid of parentheses

3x-3x-2+2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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