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3x+2x-(2x+4)=5x+2x+3-(x-5)
We move all terms to the left:
3x+2x-(2x+4)-(5x+2x+3-(x-5))=0
We add all the numbers together, and all the variables
5x-(2x+4)-(5x+2x+3-(x-5))=0
We get rid of parentheses
5x-2x-(5x+2x+3-(x-5))-4=0
We calculate terms in parentheses: -(5x+2x+3-(x-5)), so:We add all the numbers together, and all the variables
5x+2x+3-(x-5)
determiningTheFunctionDomain 5x+2x-(x-5)+3
We add all the numbers together, and all the variables
7x-(x-5)+3
We get rid of parentheses
7x-x+5+3
We add all the numbers together, and all the variables
6x+8
Back to the equation:
-(6x+8)
3x-(6x+8)-4=0
We get rid of parentheses
3x-6x-8-4=0
We add all the numbers together, and all the variables
-3x-12=0
We move all terms containing x to the left, all other terms to the right
-3x=12
x=12/-3
x=-4
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