3x+3(-x-1)=-3(x-2)

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Solution for 3x+3(-x-1)=-3(x-2) equation:



3x+3(-x-1)=-3(x-2)
We move all terms to the left:
3x+3(-x-1)-(-3(x-2))=0
We add all the numbers together, and all the variables
3x+3(-1x-1)-(-3(x-2))=0
We multiply parentheses
3x-3x-(-3(x-2))-3=0
We calculate terms in parentheses: -(-3(x-2)), so:
-3(x-2)
We multiply parentheses
-3x+6
Back to the equation:
-(-3x+6)
We add all the numbers together, and all the variables
-(-3x+6)-3=0
We get rid of parentheses
3x-6-3=0
We add all the numbers together, and all the variables
3x-9=0
We move all terms containing x to the left, all other terms to the right
3x=9
x=9/3
x=3

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