3x+3(-x-1)=-3(x-2)

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Solution for 3x+3(-x-1)=-3(x-2) equation: 



3x+3(-x-1)=-3(x-2)

We move all terms to the left:

3x+3(-x-1)-(-3(x-2))=0

We add all the numbers together, and all the variables

3x+3(-1x-1)-(-3(x-2))=0

We multiply parentheses

3x-3x-(-3(x-2))-3=0



We calculate terms in parentheses: -(-3(x-2)), so:

-3(x-2)

We multiply parentheses

-3x+6

Back to the equation:

-(-3x+6)



We add all the numbers together, and all the variables

-(-3x+6)-3=0

We get rid of parentheses

3x-6-3=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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