3x+3(4x+5)-10-2x=31

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Solution for 3x+3(4x+5)-10-2x=31 equation: 



3x+3(4x+5)-10-2x=31

We move all terms to the left:

3x+3(4x+5)-10-2x-(31)=0

We add all the numbers together, and all the variables

x+3(4x+5)-41=0

We multiply parentheses

x+12x+15-41=0

We add all the numbers together, and all the variables

13x-26=0

We move all terms containing x to the left, all other terms to the right

13x=26

x=26/13

x=2

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