3x+3(x+1)+5=2(3x)+8

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Solution for 3x+3(x+1)+5=2(3x)+8 equation: 


Simplifying
3x + 3(x + 1) + 5 = 2(3x) + 8

Reorder the terms:
3x + 3(1 + x) + 5 = 2(3x) + 8
3x + (1 * 3 + x * 3) + 5 = 2(3x) + 8
3x + (3 + 3x) + 5 = 2(3x) + 8

Reorder the terms:
3 + 5 + 3x + 3x = 2(3x) + 8

Combine like terms: 3 + 5 = 8
8 + 3x + 3x = 2(3x) + 8

Combine like terms: 3x + 3x = 6x
8 + 6x = 2(3x) + 8

Remove parenthesis around (3x)
8 + 6x = 2 * 3x + 8

Multiply 2 * 3
8 + 6x = 6x + 8

Reorder the terms:
8 + 6x = 8 + 6x

Add '-8' to each side of the equation.
8 + -8 + 6x = 8 + -8 + 6x

Combine like terms: 8 + -8 = 0
0 + 6x = 8 + -8 + 6x
6x = 8 + -8 + 6x

Combine like terms: 8 + -8 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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