3x+3(x+2)=18

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Solution for 3x+3(x+2)=18 equation: 



3x+3(x+2)=18

We move all terms to the left:

3x+3(x+2)-(18)=0

We multiply parentheses

3x+3x+6-18=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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