3x+3(x+2)=3(x+1)+12

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Solution for 3x+3(x+2)=3(x+1)+12 equation: 



3x+3(x+2)=3(x+1)+12

We move all terms to the left:

3x+3(x+2)-(3(x+1)+12)=0

We multiply parentheses

3x+3x-(3(x+1)+12)+6=0



We calculate terms in parentheses: -(3(x+1)+12), so:

3(x+1)+12

We multiply parentheses

3x+3+12

We add all the numbers together, and all the variables

3x+15

Back to the equation:

-(3x+15)



We add all the numbers together, and all the variables

6x-(3x+15)+6=0

We get rid of parentheses

6x-3x-15+6=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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