3x+3(x-2)+6=2(2x+3)+x-4

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Solution for 3x+3(x-2)+6=2(2x+3)+x-4 equation: 



3x+3(x-2)+6=2(2x+3)+x-4

We move all terms to the left:

3x+3(x-2)+6-(2(2x+3)+x-4)=0

We multiply parentheses

3x+3x-(2(2x+3)+x-4)-6+6=0



We calculate terms in parentheses: -(2(2x+3)+x-4), so:

2(2x+3)+x-4

We add all the numbers together, and all the variables

x+2(2x+3)-4

We multiply parentheses

x+4x+6-4

We add all the numbers together, and all the variables

5x+2

Back to the equation:

-(5x+2)



We add all the numbers together, and all the variables

6x-(5x+2)=0

We get rid of parentheses

6x-5x-2=0

We add all the numbers together, and all the variables

x-2=0

We move all terms containing x to the left, all other terms to the right

x=2

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