3x+3(x-2)=-41-x

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Solution for 3x+3(x-2)=-41-x equation: 



3x+3(x-2)=-41-x

We move all terms to the left:

3x+3(x-2)-(-41-x)=0

We add all the numbers together, and all the variables

3x+3(x-2)-(-1x-41)=0

We multiply parentheses

3x+3x-(-1x-41)-6=0

We get rid of parentheses

3x+3x+1x+41-6=0

We add all the numbers together, and all the variables

7x+35=0

We move all terms containing x to the left, all other terms to the right

7x=-35

x=-35/7

x=-5

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