3x+3(x-2)=2(4+x)-10

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Solution for 3x+3(x-2)=2(4+x)-10 equation: 



3x+3(x-2)=2(4+x)-10

We move all terms to the left:

3x+3(x-2)-(2(4+x)-10)=0

We add all the numbers together, and all the variables

3x+3(x-2)-(2(x+4)-10)=0

We multiply parentheses

3x+3x-(2(x+4)-10)-6=0



We calculate terms in parentheses: -(2(x+4)-10), so:

2(x+4)-10

We multiply parentheses

2x+8-10

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

6x-(2x-2)-6=0

We get rid of parentheses

6x-2x+2-6=0

We add all the numbers together, and all the variables

4x-4=0

We move all terms containing x to the left, all other terms to the right

4x=4

x=4/4

x=1

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