3x+3(x-2)=3(x+6)

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Solution for 3x+3(x-2)=3(x+6) equation: 



3x+3(x-2)=3(x+6)

We move all terms to the left:

3x+3(x-2)-(3(x+6))=0

We multiply parentheses

3x+3x-(3(x+6))-6=0



We calculate terms in parentheses: -(3(x+6)), so:

3(x+6)

We multiply parentheses

3x+18

Back to the equation:

-(3x+18)



We add all the numbers together, and all the variables

6x-(3x+18)-6=0

We get rid of parentheses

6x-3x-18-6=0

We add all the numbers together, and all the variables

3x-24=0

We move all terms containing x to the left, all other terms to the right

3x=24

x=24/3

x=8

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