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3x+3+2(x-3)=5(x-2)+5x
We move all terms to the left:
3x+3+2(x-3)-(5(x-2)+5x)=0
We multiply parentheses
3x+2x-(5(x-2)+5x)-6+3=0
We calculate terms in parentheses: -(5(x-2)+5x), so:We add all the numbers together, and all the variables
5(x-2)+5x
We add all the numbers together, and all the variables
5x+5(x-2)
We multiply parentheses
5x+5x-10
We add all the numbers together, and all the variables
10x-10
Back to the equation:
-(10x-10)
5x-(10x-10)-3=0
We get rid of parentheses
5x-10x+10-3=0
We add all the numbers together, and all the variables
-5x+7=0
We move all terms containing x to the left, all other terms to the right
-5x=-7
x=-7/-5
x=1+2/5
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