3x+3-5x=12-(6x-7)

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Solution for 3x+3-5x=12-(6x-7) equation: 



3x+3-5x=12-(6x-7)

We move all terms to the left:

3x+3-5x-(12-(6x-7))=0

We add all the numbers together, and all the variables

-2x-(12-(6x-7))+3=0



We calculate terms in parentheses: -(12-(6x-7)), so:

12-(6x-7)

determiningTheFunctionDomain
-(6x-7)+12

We get rid of parentheses

-6x+7+12

We add all the numbers together, and all the variables

-6x+19

Back to the equation:

-(-6x+19)



We get rid of parentheses

-2x+6x-19+3=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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