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3x+3/2x=90
We move all terms to the left:
3x+3/2x-(90)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
3x*2x-90*2x+3=0
Wy multiply elements
6x^2-180x+3=0
a = 6; b = -180; c = +3;
Δ = b2-4ac
Δ = -1802-4·6·3
Δ = 32328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32328}=\sqrt{36*898}=\sqrt{36}*\sqrt{898}=6\sqrt{898}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-6\sqrt{898}}{2*6}=\frac{180-6\sqrt{898}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+6\sqrt{898}}{2*6}=\frac{180+6\sqrt{898}}{12} $
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