3x+32+9x+74=5(2x-12)-4x

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Solution for 3x+32+9x+74=5(2x-12)-4x equation: 



3x+32+9x+74=5(2x-12)-4x

We move all terms to the left:

3x+32+9x+74-(5(2x-12)-4x)=0

We add all the numbers together, and all the variables

12x-(5(2x-12)-4x)+106=0



We calculate terms in parentheses: -(5(2x-12)-4x), so:

5(2x-12)-4x

We add all the numbers together, and all the variables

-4x+5(2x-12)

We multiply parentheses

-4x+10x-60

We add all the numbers together, and all the variables

6x-60

Back to the equation:

-(6x-60)



We get rid of parentheses

12x-6x+60+106=0

We add all the numbers together, and all the variables

6x+166=0

We move all terms containing x to the left, all other terms to the right

6x=-166

x=-166/6

x=-27+2/3

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