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3x+32x-5=7(5x+4)
We move all terms to the left:
3x+32x-5-(7(5x+4))=0
We add all the numbers together, and all the variables
35x-(7(5x+4))-5=0
We calculate terms in parentheses: -(7(5x+4)), so:We get rid of parentheses
7(5x+4)
We multiply parentheses
35x+28
Back to the equation:
-(35x+28)
35x-35x-28-5=0
We add all the numbers together, and all the variables
-33!=0
There is no solution for this equation
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