3x+33=6(3-2x)

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Solution for 3x+33=6(3-2x) equation: 



3x+33=6(3-2x)

We move all terms to the left:

3x+33-(6(3-2x))=0

We add all the numbers together, and all the variables

3x-(6(-2x+3))+33=0



We calculate terms in parentheses: -(6(-2x+3)), so:

6(-2x+3)

We multiply parentheses

-12x+18

Back to the equation:

-(-12x+18)



We get rid of parentheses

3x+12x-18+33=0

We add all the numbers together, and all the variables

15x+15=0

We move all terms containing x to the left, all other terms to the right

15x=-15

x=-15/15

x=-1

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