3x+38=2(6x+1)

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Solution for 3x+38=2(6x+1) equation:



3x+38=2(6x+1)
We move all terms to the left:
3x+38-(2(6x+1))=0
We calculate terms in parentheses: -(2(6x+1)), so:
2(6x+1)
We multiply parentheses
12x+2
Back to the equation:
-(12x+2)
We get rid of parentheses
3x-12x-2+38=0
We add all the numbers together, and all the variables
-9x+36=0
We move all terms containing x to the left, all other terms to the right
-9x=-36
x=-36/-9
x=+4

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