3x+3x/(x+1)=2/(x+1)

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Solution for 3x+3x/(x+1)=2/(x+1) equation: 



3x+3x/(x+1)=2/(x+1)

We move all terms to the left:

3x+3x/(x+1)-(2/(x+1))=0



Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R





Domain of the equation: (x+1))!=0

x∈R



We calculate fractions


6x^2/((x+1)*(x+1)))+(+3x-(2*(x+1))/((x+1)*(x+1)))=0



We calculate terms in parentheses: -(2*(x+1))/((x+1)*(x+1))), so:

2*(x+1))/((x+1)*(x+1))

We multiply all the terms by the denominator


2*(x+1))

We multiply parentheses

2x+

We add all the numbers together, and all the variables

2x

Back to the equation:

-(2x)



We add all the numbers together, and all the variables

6x^2/((x+1)*(x+1)))+(+x=0

We multiply all the terms by the denominator


6x^2+x*((x+1)*(x+1)))+(=0

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