3x+4(-1/2x+8=36

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Solution for 3x+4(-1/2x+8=36 equation: 



3x+4(-1/2x+8=36

We move all terms to the left:

3x+4(-1/2x+8-(36)=0



Domain of the equation: 2x+8-36!=0

We move all terms containing x to the left, all other terms to the right

2x!=28

x!=28/2

x!=14

x∈R



We multiply all the terms by the denominator


3x*2x+8-36+4(-1=0

We add all the numbers together, and all the variables

3x*2x=0

Wy multiply elements

6x^2=0

a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$

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