3x+4(2-x)=3(x+2)-4

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Solution for 3x+4(2-x)=3(x+2)-4 equation: 



3x+4(2-x)=3(x+2)-4

We move all terms to the left:

3x+4(2-x)-(3(x+2)-4)=0

We add all the numbers together, and all the variables

3x+4(-1x+2)-(3(x+2)-4)=0

We multiply parentheses

3x-4x-(3(x+2)-4)+8=0



We calculate terms in parentheses: -(3(x+2)-4), so:

3(x+2)-4

We multiply parentheses

3x+6-4

We add all the numbers together, and all the variables

3x+2

Back to the equation:

-(3x+2)



We add all the numbers together, and all the variables

-1x-(3x+2)+8=0

We get rid of parentheses

-1x-3x-2+8=0

We add all the numbers together, and all the variables

-4x+6=0

We move all terms containing x to the left, all other terms to the right

-4x=-6

x=-6/-4

x=1+1/2

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