3x+4(2x+8-3x+2)=21x+7(5x+8-36x)

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Solution for 3x+4(2x+8-3x+2)=21x+7(5x+8-36x) equation:



3x+4(2x+8-3x+2)=21x+7(5x+8-36x)
We move all terms to the left:
3x+4(2x+8-3x+2)-(21x+7(5x+8-36x))=0
We add all the numbers together, and all the variables
3x+4(-1x+10)-(21x+7(-31x+8))=0
We multiply parentheses
3x-4x-(21x+7(-31x+8))+40=0
We calculate terms in parentheses: -(21x+7(-31x+8)), so:
21x+7(-31x+8)
We multiply parentheses
21x-217x+56
We add all the numbers together, and all the variables
-196x+56
Back to the equation:
-(-196x+56)
We add all the numbers together, and all the variables
-1x-(-196x+56)+40=0
We get rid of parentheses
-1x+196x-56+40=0
We add all the numbers together, and all the variables
195x-16=0
We move all terms containing x to the left, all other terms to the right
195x=16
x=16/195
x=16/195

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