3x+4(2x+8-3x+2)=21x+7(5x+8-36x)

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Solution for 3x+4(2x+8-3x+2)=21x+7(5x+8-36x) equation: 



3x+4(2x+8-3x+2)=21x+7(5x+8-36x)

We move all terms to the left:

3x+4(2x+8-3x+2)-(21x+7(5x+8-36x))=0

We add all the numbers together, and all the variables

3x+4(-1x+10)-(21x+7(-31x+8))=0

We multiply parentheses

3x-4x-(21x+7(-31x+8))+40=0



We calculate terms in parentheses: -(21x+7(-31x+8)), so:

21x+7(-31x+8)

We multiply parentheses

21x-217x+56

We add all the numbers together, and all the variables

-196x+56

Back to the equation:

-(-196x+56)



We add all the numbers together, and all the variables

-1x-(-196x+56)+40=0

We get rid of parentheses

-1x+196x-56+40=0

We add all the numbers together, and all the variables

195x-16=0

We move all terms containing x to the left, all other terms to the right

195x=16

x=16/195

x=16/195

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