3x+4(2x-10)=6x-120

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Solution for 3x+4(2x-10)=6x-120 equation: 



3x+4(2x-10)=6x-120

We move all terms to the left:

3x+4(2x-10)-(6x-120)=0

We multiply parentheses

3x+8x-(6x-120)-40=0

We get rid of parentheses

3x+8x-6x+120-40=0

We add all the numbers together, and all the variables

5x+80=0

We move all terms containing x to the left, all other terms to the right

5x=-80

x=-80/5

x=-16

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