3x+4(2x-3)=6(x-2)+5x

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Solution for 3x+4(2x-3)=6(x-2)+5x equation: 



3x+4(2x-3)=6(x-2)+5x

We move all terms to the left:

3x+4(2x-3)-(6(x-2)+5x)=0

We multiply parentheses

3x+8x-(6(x-2)+5x)-12=0



We calculate terms in parentheses: -(6(x-2)+5x), so:

6(x-2)+5x

We add all the numbers together, and all the variables

5x+6(x-2)

We multiply parentheses

5x+6x-12

We add all the numbers together, and all the variables

11x-12

Back to the equation:

-(11x-12)



We add all the numbers together, and all the variables

11x-(11x-12)-12=0

We get rid of parentheses

11x-11x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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