3x+4(2x-5)=7(5x+2)-10

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Solution for 3x+4(2x-5)=7(5x+2)-10 equation: 



3x+4(2x-5)=7(5x+2)-10

We move all terms to the left:

3x+4(2x-5)-(7(5x+2)-10)=0

We multiply parentheses

3x+8x-(7(5x+2)-10)-20=0



We calculate terms in parentheses: -(7(5x+2)-10), so:

7(5x+2)-10

We multiply parentheses

35x+14-10

We add all the numbers together, and all the variables

35x+4

Back to the equation:

-(35x+4)



We add all the numbers together, and all the variables

11x-(35x+4)-20=0

We get rid of parentheses

11x-35x-4-20=0

We add all the numbers together, and all the variables

-24x-24=0

We move all terms containing x to the left, all other terms to the right

-24x=24

x=24/-24

x=-1

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