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3x+4(x+1)=x+2(x+3)
We move all terms to the left:
3x+4(x+1)-(x+2(x+3))=0
We multiply parentheses
3x+4x-(x+2(x+3))+4=0
We calculate terms in parentheses: -(x+2(x+3)), so:We add all the numbers together, and all the variables
x+2(x+3)
We multiply parentheses
x+2x+6
We add all the numbers together, and all the variables
3x+6
Back to the equation:
-(3x+6)
7x-(3x+6)+4=0
We get rid of parentheses
7x-3x-6+4=0
We add all the numbers together, and all the variables
4x-2=0
We move all terms containing x to the left, all other terms to the right
4x=2
x=2/4
x=1/2
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