3x+4(x+2)=8x+1

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Solution for 3x+4(x+2)=8x+1 equation: 



3x+4(x+2)=8x+1

We move all terms to the left:

3x+4(x+2)-(8x+1)=0

We multiply parentheses

3x+4x-(8x+1)+8=0

We get rid of parentheses

3x+4x-8x-1+8=0

We add all the numbers together, and all the variables

-1x+7=0

We move all terms containing x to the left, all other terms to the right

-x=-7

x=-7/-1

x=+7

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