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3x+4(x+3)=3(x+8)
We move all terms to the left:
3x+4(x+3)-(3(x+8))=0
We multiply parentheses
3x+4x-(3(x+8))+12=0
We calculate terms in parentheses: -(3(x+8)), so:We add all the numbers together, and all the variables
3(x+8)
We multiply parentheses
3x+24
Back to the equation:
-(3x+24)
7x-(3x+24)+12=0
We get rid of parentheses
7x-3x-24+12=0
We add all the numbers together, and all the variables
4x-12=0
We move all terms containing x to the left, all other terms to the right
4x=12
x=12/4
x=3
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