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3x+4(x+5)=3(2x-5)
We move all terms to the left:
3x+4(x+5)-(3(2x-5))=0
We multiply parentheses
3x+4x-(3(2x-5))+20=0
We calculate terms in parentheses: -(3(2x-5)), so:We add all the numbers together, and all the variables
3(2x-5)
We multiply parentheses
6x-15
Back to the equation:
-(6x-15)
7x-(6x-15)+20=0
We get rid of parentheses
7x-6x+15+20=0
We add all the numbers together, and all the variables
x+35=0
We move all terms containing x to the left, all other terms to the right
x=-35
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